tan(a+b)=1/3 and tan(a-b) =2/5, prove that tan2a=11/3
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Step-by-step explanation: I hope this helps you please mark as brainliest answer
Hi ,
Tan(A+B)= 1/2 ---( 1 )
Tan(A -B) = 1/3-----( 2 )
Tan(2A)
=Tan[(A+B)+(A-B)]
=[Tan(A+B)+Tan(A-B)]/[1-tan(A+B)tan(A-B)]
= [1/2+1/3]/[1-1/2×1/3]
=[(3+2)/6]/[(6-1)/6]
=[5/6]/[5/6]
= 1
Therefore,
Tan 2A = 1
I hope this helps you.
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