Question

Tan{a+b/2}= cot{c/2}

Answer 1

$a + b + c = 180(for \: any \: triangle) \\ a + b = 180 - c \\ \frac{ a+b }{2} = 90 - \frac{c}{2} \\tan \frac{a + b}{2} = tan \frac{9 0 - c}{2} \\ tan \frac{a + b}{2} = cot \frac{c}{2}$

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