Tan (A+B) = √3 and Tan A =1 find the measure of B.
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Tan(A+B)=√3
A+B=60 {Tan 60°=√3}
∴A=60-B----(1)
Given, TanA=1
A=90° {tan 90°=1}
from (1),90=60-B
∴B=60-90= -30
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