Question

tan (A+B) = √3 and tan (A-B) =1
find the value of
A and B..​

Answer 1

Answer:

So easy question... Wait I will explain you

Step-by-step explanation:

• Given-tan(A+B)=√3 and tan(A-B)=1

• (A+B)=√3 - 1eq.
• (A-B)=1 - 2 eq.
• on eliminating 1 and 2 eq
• A+B=√3
• A-B=1
• = A=√3-1
• putting the value of A in 1eq.
• √3-1 +B=√3
• B=√3-√3 +1
• B=1
• So the value of A=√3-1 And B=1
• Thank you hope it will be helpful to you.

Answer 2

tan(A+B) = √3 and tan60°=√3

=(A+B) = 60° -(i)

&

tan(A-B) =1/√3 and tan30°=1/√3

=(A-B) =1/√3 -(ii)

(i) +(ii)

A+B=60°+ (A-B=30°) [ab +B, -B se cut jaega]

= 2A=90°

=A=90°/2

=A=45°

putting value of A in (i)

A+B=60°

45°+B =60°

B= 60°-45°

B=15°

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