tan ( a+b)=√3 ,tan a=1then tan b=?
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Given, Tan (a+b) = √3
( we know - tan (60°) = √3 )
=> tan (a+b) = tan(60°) --------eq(1)
And also given, tan a = 1
( we know - tan (45°) = 1 )
=> tan a = tan (45°) -----------eq(2)
Substituting eq(2) in eq(1)
tan ( 45° + b) = tan ( 60° )
45° + b = 60°
b = 15°
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