tan(A-B) =7/24, tan A=4/3, where A,B are acute angles then A+B=?
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Tan(A-B)= tanA-tanB
——————
1 +tanA tanB
7/24 = (4/3 -x)/1+ 4/3x
Where x=tanB
So 7/24 = 4-3x/3(3+4x)/3
7/24= 4-3x /3+4x
7(3+4x)=24(4-3x)
21+28x=96-72x
100x= 75
X = 3/4
Tan(A+B)= (tanA+tanB )/ 1-tanA tanB
= (4/3+3/4)/1-1 = infinity
So A+B= 90 degrees
——————
1 +tanA tanB
7/24 = (4/3 -x)/1+ 4/3x
Where x=tanB
So 7/24 = 4-3x/3(3+4x)/3
7/24= 4-3x /3+4x
7(3+4x)=24(4-3x)
21+28x=96-72x
100x= 75
X = 3/4
Tan(A+B)= (tanA+tanB )/ 1-tanA tanB
= (4/3+3/4)/1-1 = infinity
So A+B= 90 degrees
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