Tan A+B-C/2 = Cot C prove it.
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A+B+C=180
(A+B+C)/2=90
(A+B)/2=(90-C/2)---(1)
Lhs = tan(A+B-C/2)
=tan(90-C/2-C/2)
=tan(90-C)
=cotC
=rhs
(A+B+C)/2=90
(A+B)/2=(90-C/2)---(1)
Lhs = tan(A+B-C/2)
=tan(90-C/2-C/2)
=tan(90-C)
=cotC
=rhs
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