Question

tan (A+B-C)+tan (B+C-A)+tan (C+A-B) = tan (A+B-C) tan (B+C-A) tan (C+A-B)​

Answer 1

Step-by-step explanation:

By Tiwary Ramesh

Amrit Campus

Kathmandu

Answer 2

Answer:

Step-by-step explanation:

tan(A + B - C) + Tan(B + C - A) + Tan(C + A - B) = T

(A+B-C) tan (B+C-A). tan(C + A - B) .

Let

B + w - A = x C + A - B = Y

+ A + B - C = 2

A + B + C = x + y + z

where, A + B + C =180:

So, x + y + 2 = 180 deg

x + 1 = 180 deg - z

tan(x + y) .=tan(180-2) tan( x + y = - tan z

(tan x + tan y)/(1 - tan x - tan y) - fanz

tan x + tan y =-tan z+tan x* tan y.tan z .

tan x + tan y + tan z =tan x.tan y.tan z.

tan(B + c - A) + lan(C + A - B) +lan(A+B-c

)

tan(B + c - A) * tan(C + A - B) * tan(A + B - C)