tan a + b equal to root 2 and 10 a minus b equal to 1 then find the value of a and b
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1
Answer:
Given tan(A+B)=
3
⟹A+B=60
∘
⋯(1)
tan(A−B)=
3
1
⟹A−B=30
∘
⋯(2)
(1)+(2)⟹2A=90
∘
⟹A=45
∘
Put A value in (1)
⟹B=60
∘
−45
∘
=15
∘
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