Question

tan=a/b
find asin-bcos/asin+bcos​

Answer 1

We know that

tan

θ

=

sin

θ

cos

θ

, so we know that

sin

θ

=

a

and

cos

θ

=

b

a

sin

θ

−

b

cos

θ

a

sin

θ

+

b

cos

θ

=

a

(

a

)

−

b

(

b

)

a

(

a

)

+

b

(

b

)

This can be written as

a

2

−

b

2

a

2

+

b

2

.

Hopefully this helps!