Question

tan =a/b then sin =​

Answer 1

Answer:

$tan =\frac{a}{b} = \frac{p}{b}$

using Pythagoras theorem

$h^{2} = p^{2} + b^{2}$

$h^{2} = (a)^{2} + (b)^{2}$

$h^{2} = a^{2} + b^{2}$

$h = \sqrt{a^{2} + b^{2}}$

$sin = \frac{p}{h} = \frac{a}{\sqrt{a^{2} + b^{2}}}$

Answer 2

Answer:

P/√P²+B²

=a/√a²+b²

Step-by-step explanation:

tan Q =a/b=P/B

H²=P²+B²

H=√P²+B²

sin Q= P/H

=P/√P²+B²

=a/√a²+b²

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