Question

tan(A-B) when tanA=√3/4-√3 and tanB=√3/4+√3​

Answer 1

Step-by-step explanation:

• tan (a-b)= tana-tanb÷1+tanatanb
• tan(a-b)=√3÷4-√3-{√3/4+√3}÷1+√3/4-√3×√3/4+√3=0