tan (A+B) =x,
tan (A-B) =y
find tan 2A
tan 2B
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Answer:
Tan2B=(x-y)/(1+xy).
Explanation:
Tan2A=tan[(A+B)+(A-B)]
Expanding using identity of tan
tan2A={tan(A+B)+tan(A-B)}/{1-tan(A+B)tan(A-B)}
Given tan(A+B)=x and tan(A-B)=y
Substituting these values in tan2A expression we get
Tan2A=(x+y)/(1-xy)
Tan2B=tan[(A+B)-(A-B)]
Tan2B=[tan(A+B)-tan(A-B)]/[1+tan(A+B)tan(A-B)]
Resubstituting the values we get
Tan2B=(x-y)/(1+xy).
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