tan A+ COLA
9.
(iv) (sec A+ cos A) (sec A-Cos A) = tan? A + sin? A
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2
Answer:
the answer is 2
Step-by-step explanation:
(secA+cosA) (secA-cosA)
=sec²A - cos²A [(a+b) (a-b) = a²+b²]
we know that cos²A = 1-sin²A and sec²A = 1+tan²A
= 1+tan²A -(1-sin²A)
= 1+tan²A -1+sin²A
= tan²A + sin²A
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