Question

tan A+ Cosec B = 3, A = 30° and B is an acute angle then find the value of B.
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Answer 1

tan A + cosec B = 3

tan 30° + cosec B = 3

1/√3 + cosec B = 3

cosec B = 3 - 1/√3

cosec B = (3√3 - 1)/√3

B = cosec¯¹ [(3√3 - 1)/√3]