tan A+ Cosec B = 3, A = 30° and B is an acute angle then find the value of B.
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tan A + cosec B = 3
tan 30° + cosec B = 3
1/√3 + cosec B = 3
cosec B = 3 - 1/√3
cosec B = (3√3 - 1)/√3
B = cosec¯¹ [(3√3 - 1)/√3]
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