Question

tan A + cot A =2 find sinA​

Answer 1

It’s just a quadratic equation... Please Brainlist this

Answer 2

Tan A + Cot A =2

Tan A +1/TanA = 2

Tan A +1/Tan A -2=0

(TanA)^2 +1-2TanA = 0×TanA

(TanA)^2 -TanA-TanA +1=0

TanA(TanA-1)-1(TanA-1)=0

(TanA-1)(TanA-1) =0

Tan A = 1

A = 45°

so ,

sin A = sin 45°=(1/√2)

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