Tan a+cot a=2,then find tan ^a-cot^2a
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Hey !!
tanA + cotA = 2 (given )
then ur question. is tan²A - cot²A = ?
(tanA+cotA)²-4tanA×cotA= (tan-cota)²
(a+b)² - 4ab = ( a + b)²
2² - 4×1 = (tanA-cotA)²
4 - 4 = tan²A -cot²A
0 = tan²A - cot²A
hence , tan²A - cot²A = 0
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Hope it helps you !!!
@Rajukumar111
tanA + cotA = 2 (given )
then ur question. is tan²A - cot²A = ?
(tanA+cotA)²-4tanA×cotA= (tan-cota)²
(a+b)² - 4ab = ( a + b)²
2² - 4×1 = (tanA-cotA)²
4 - 4 = tan²A -cot²A
0 = tan²A - cot²A
hence , tan²A - cot²A = 0
****************************
Hope it helps you !!!
@Rajukumar111
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