Question

Tan A - Cot A = 2Sin² A - 1 / Sin A . Cos A​

Answer 1

Answer:

LHS = tanA - cotA

       = $\frac{sinA}{cosA}$ - $\frac{cosA}{sinA}$

       = $\frac{sin^2A - cos^2A}{sinAcosA}$

       = $\frac{sin^2A - ( 1- sin^2A)}{sinAcosA}$                               ( ∵ $sin^{2} A + cos^{2} A = 1$ )

       = $\frac{sin^2A-1+sin^2A}{sinAcosA}$

       = $\frac{2sin^2A-1}{sinAcosA}$   = RHS --------------- proved

Answer 2

Answer:

ur ans is here ☺️

sorry for all d mess

actually I cannot solve mathematics without cuts n crosses.....

hope this helps uh !