Question

tan A + cot A= (sec A) (cosec A)​

Answer 1

$\huge\star\underline{\mathtt\red{A}\mathtt\green{N}\mathtt\blue{S}\mathtt\purple{W}\mathtt\orange{E}\mathtt\pink{R}}\star\:$

$\bold{tan A + cot A = (sec A) (cosec A)}$

=> $\dfrac{sin A }{cos A} + \dfrac{cos A}{sin A}$

=> $\dfrac{sin² A + cos² A}{(cos A)(sin A)}$

(∵ sin² A + cos² A = 1 )

=> $\dfrac{1}{(cos A)(sin A)}$

=> (sec A) (cosec A)