tan a+cota =(sec^2a +cosec^2a)^1/2
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hey... your answer is here......................
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NOTkethan:
Dude how is 1/SinACosA=sinA/cosA+cosA/sinA
not kethan u just solve that upto 1/cosAsinA and then prove tanA+cotA u will get LHS=RHS
1/sina+ 1/cosa = sin^2a + cos^2a/sinacosa=sina/cosa+cosa/sina
That is also wrong
i think u are not understanding
ok
okay
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RHS=(sec^2a +cosec^2a)^1/2=(1/cos²A+1/Sin²A)^1/2=(1/cosA+1/sinA)
=(sinA+cosA)/cosAsinA (LCM)
=sinA/cosA+cosA/sinA (separating to convert to Tan and Cot)
=tanA+cotA
∴LHS=RHS
=(sinA+cosA)/cosAsinA (LCM)
=sinA/cosA+cosA/sinA (separating to convert to Tan and Cot)
=tanA+cotA
∴LHS=RHS
Pls mark it brainliest
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