Question

tan A is equal to root 2 minus 1 then the value of sin A is

Answer 1

sinA =
$\sqrt{2(2 + \sqrt{2)} }$

Answer 2

tan A = √2-1/1
P/B=√2-1/1
P=√2-1 , B=1
BY Pythagoras theorem
H^2= (√2-1)^2+1^2
H^2=2+1-2√2=+1
= 4-2√2
$h = \sqrt{4 - 2 \sqrt{2} }$
sin A=
$\frac{ \sqrt{2 } - 1 }{ \sqrt{4 - 2 \sqrt{2} } }$