Question

Tan A ko Sec a ke pado me byakt Karo
plz explain urgent hay na​

Answer 1

we know that

1+tanx²= secx²

then ,

secx = √ 1+tan x

I hope it helps you

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Answer 2

1+ tan x² = sec x²

therefore

$\sec(x) = \sqrt{1 + \tan {}^{2} (x) }$

i hope it helps you.

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