Question

tan A=
O a. 1/(J1-sin-A)
b. (sin A)//(1-sin2A)
O c. (cos A)//(1-COSA)
O d. (sec A)//(1-sec A)
Clear my choice
rapid answer ​

Answer 1

tanA = sinA/1-sin^2A

1-sin^2A=cos^2A

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