tan A+ sec A-1/tan A-sec A+1=1+sinA /cos A
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ALWAYS REMEMBER WHEREVER YOU SEE SAME TERMS LIKE TAN A+SEC A IMMEDIATELY APPLY ANY TRIGONOMETRIC IDENTITY.
ALSO,I HAVE USED (SEC A-TAN A)(SEC A+TAN A) USING THE IDENTITY (a^2-b^2)
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Answer:
LHS, tanA+secA-1/tanA-secA+1
=tanA+secA-(sec²A-tan²A)/tanA-secA+1
=tanA+secA+tan²A-sec²A/tanA-secA+1
=tanA+secA+(tanA+secA)(tanA-secA)/tanA-secA+1
=tanA+secA(1+tanA-secA)/(tanA-secA+1)
=tanA+secA
=sinA/cosA + 1/cosA
=sinA+1/cosA
IDENTITIES USED
sec²A=1+tan²A
x²-y²=(x+y)(x-y)
Step-by-step explanation:
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