tan A/sec A -1 +tan A / secA + 1 =2cosecA
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Answer:
Taking L. H. S.
=tanA/secA-1+tanA/sec+1
TAKING L. C. M.
=tanA(secA+1+secA-1/sec²-1)
=tanA(2secA/tan²A)
=2secA/tanA
=2 x 1/cosA x cosA/sinA
=2/sinA
=2cosecA
HOPE IT WILL HELP U DEAR
Step-by-step explanation:
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