Math, asked by khushigupta96, 1 year ago

tan A/sec A -1 +tan A / secA + 1 =2cosecA​

Answers

Answered by argupta0904
2

Answer:

Taking L. H. S.  

=tanA/secA-1+tanA/sec+1

TAKING L. C. M.  

=tanA(secA+1+secA-1/sec²-1)  

=tanA(2secA/tan²A)

=2secA/tanA

=2 x 1/cosA x cosA/sinA

=2/sinA

=2cosecA

HOPE IT WILL HELP U DEAR

Step-by-step explanation:

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Answered by thara135
1

the answer is attached above

Attachments:
khushigupta96: ty a ton
thara135: you're welcome
argupta0904: I thought I can help you
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