Question

(tan a + seca)^2- ( tan a-sec a )^2 ​

Answer 1

Answer:

Hope it helps you

Step-by-step explanation:

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Answer 2

Answer:

4x tan a x sec a

Step-by-step explanation:

we know that

(a^2-b^2)= (a+b)(a-b)

so let consider (tan a + sec a) as x

and (tan a -sec a) as y

now, we get ( x^2 - y^2) from the given equation

now (x^2-y^2)= (x+y)(x-y)

=(tan a+sec a + tan a - sec a). (tan a + sec a

-( tan a - sec a))

= ( 2 tan a). ( tan a + sec a - tan a + sec a)

=2 tan a. 2 sec a

=4 tan a sec a