Math, asked by anusha301, 1 year ago

tan A × sin A + cos A = sec A

Answers

Answered by Anonymous

20

Answer:

tanA×sinA+cosA=secA

Taking LHS.,,

tanA×sinA+cosA

→sinA/cosA × sinA +cosA

→(sin^2A+cos^2A)/cosA

→1/cosA

→secA

LHS=RHS

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Answered by GRANDxSAMARTH

2

tanAxsinA+COSA=secA

Taking LHS.,

->tanAxsinA+COSA

->sinA/COSA x sinA +COSA

->(sin^2A+cos^2A)/COSA

->1/COSA

->SecA

LHS=RHS

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