tan A × sin A + cos A = sec A
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Answered by
20
Answer:
tanA×sinA+cosA=secA
Taking LHS.,,
tanA×sinA+cosA
→sinA/cosA × sinA +cosA
→(sin^2A+cos^2A)/cosA
→1/cosA
→secA
LHS=RHS
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Answered by
2
tanAxsinA+COSA=secA
Taking LHS.,
->tanAxsinA+COSA
->sinA/COSA x sinA +COSA
->(sin^2A+cos^2A)/COSA
->1/COSA
->SecA
LHS=RHS
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