tan A × sin A + cos A=secA show that
Answers
Answered by
1
Answer:
Consider LHS =tanAsinA+cosA
=
cosA
sinA
sinA+cosA (∵tanA=
cosA
sinA
)
=
cosA
sin
2
A
+cosA=
cosA
sin
2
A+cos
2
A
(But sin
2
A+cos
2
A=1)
=
cosA
1
=secA= RHS
Answered by
4
Answer:
tana x sinA + cosA
=sinA/cosA x sinA + cos A
=sin²A+cos²A/cos A
=1/cosA
=secA
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