Question

tan A + sin A/tan A - sin A =sec A +1/ sec A -1

Answer 1

Step-by-step explanation:

$\frac{tan A+sinA}{tan A - sin A} = \frac{\frac{sinA}{cosA}+\frac{sinAcosA}{cosA}}{\frac{sinA}{cosA}-\frac{sinAcosA}{cosA}}=\frac{\frac{sinA}{cosA}(1+cosA)}{\frac{sinA}{cosA}(1-cosA)} =\frac{1+cosA}{1-cosA}=\frac{1+\frac{1}{secA}}{1-\frac{1}{secA}}$

=>$\frac{\frac{secA+1}{secA}}{\frac{secA-1}{secA}}=\frac{secA +1}{secA-1}$

Hence Proved.

Thank u

Plzzz mark mine as brainliest.