tan A=sinA/cosA plzz explain how it this will come
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Answered by
0
tan A = Opposite side/adjacent side
tan A = (SinA × hypotenuse)/ (CosA × hypotenuse)
{ because you know SinA = opposite/hypotenuse and Cos A = adjacent/hypotenuse}
so , tan A = SinA/CosA
{ hypotenuse will be cancelled in both the denominator and the numerator}
Hence , tan A = SinA / CosA
tan A = (SinA × hypotenuse)/ (CosA × hypotenuse)
{ because you know SinA = opposite/hypotenuse and Cos A = adjacent/hypotenuse}
so , tan A = SinA/CosA
{ hypotenuse will be cancelled in both the denominator and the numerator}
Hence , tan A = SinA / CosA
seenvasreddy:
thanq sir
Answered by
1
sinA=parpendicular/hypotenous
cosA=base/hypotenous
so, sinA/cosA
=p/h÷b/h
=p/h×b/h
=p/b
=tanA
Don't forget to press thank u bottom.
cosA=base/hypotenous
so, sinA/cosA
=p/h÷b/h
=p/h×b/h
=p/b
=tanA
Don't forget to press thank u bottom.
thanks
welcum
what is ph and bh can it be still more clear
p means perpendicular, b means base and h means hypotenous
sir in the above devision p/hxh/b then u will come to p/b is it correct sir
in p/h×h/b denominator of p/h is h and numirator of h/b is h cancelled and the remaining ans is p/b
u should write the solution by own then only u can understand.
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