Math, asked by larebrehmani, 6 hours ago

tan A + tan A÷
sec A-1 sec A +1​

Answers

Answered by 7cbsivasai31649
0

L.H.S

1+secAtanA−1−secAtanA

=1−sec2AtanA(1−secA)−tanA(1+secA)

=−tan2AtanA(1−secA−1−secA)

=−tanA−2secA

=sinA/cosA2⋅1/cosA

=sinA2

=2⋅cosecA

=R.H.S

∴ L.H.S=R.H.S.

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