Question

tan A, tan B roots of
If
3.x2 – 10x – 25 = 0 then value of
3sin? (A+B)-10 sin( A+B) cos(A+B)-​

Answer 1

Answer:

please make me brainliest and follow me

Step-by-step explanation:

Given, 3x

2

−10x−25=0

tanA+tanB=

3

10

tanA×tanB=

3

−25

tan(A+B)=

1−tanAtanB

tanA+tanB

1+

3

25

3

10

3

28

3

10

=

28

10

=

14

5

∴tan(A+B)=

14

5

∴sin(A+B)=

221

5

cos(A+B)=

221

14

∴3sin

2

(A+B)−10sin(A+B)cos(A+B)−25cos

2

(A+B)

=3×

221

25

−10×

221

70

−25×

221

196

=

221

75−700−4900

=−25