Math, asked by sulemanjiwani44, 10 months ago

tan A + tan B
tan (A+B)
tan A-tan B
tan ( A - B)​

Answers

Answered by Anonymous
1

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tan(A+B) =( tanA + tanB)/ (1-tanAtanB)

tan(A-B)=(tanA- tanB)/(1+tanAtanB)

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Answered by Anonymous
3

tan (A+B)=tan A+ tan B /1-tanAtanB

tan (A-B) =tan A-tan B/1+tanAtanB

tan A+tanB= [tan (A+B)][1-tanAtanB]

tan A-tan B=[tan (A-B)][1+tanAtanB]

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