tan A + tan B
tan (A+B)
tan A-tan B
tan ( A - B)
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Answered by
1
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tan(A+B) =( tanA + tanB)/ (1-tanAtanB)
tan(A-B)=(tanA- tanB)/(1+tanAtanB)
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Answered by
3
tan (A+B)=tan A+ tan B /1-tanAtanB
tan (A-B) =tan A-tan B/1+tanAtanB
tan A+tanB= [tan (A+B)][1-tanAtanB]
tan A-tan B=[tan (A-B)][1+tanAtanB]
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