Question

tan alpha =1,tan beta=2,tan gamma=3 then alpha + beta + gamma​

Answer 1

Answer:

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Answer 2

Answer:

tan A = 1, tan B = 2, tan C = 3 (let alpha =A, beta = B, gama = C)

we know tan (A+B+C) = (tan A + tan B+ tan C – tanA *tanB *tanC)/ (1 – tanA *tanB – tanB *tanC – tanC *tanA)

now put the value,

tan(A+B+C) = (1 +2 +3 – 6)/(1 – 2 – 6 – 3)

tan(A+B+C) = 0/( – 10)

tan(A+B+C) = 0

hence

A+B+C = 0