Question

tan alpha = cot beta = a, find (alpha + beta)​

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

given : $\tan \alpha =\cot \beta =a$

To find : $(\alpha +\beta)$

explanation:

$\tan \alpha =\cot \beta =a \\\\\tan \alpha= \frac{1}{\tan \beta}=a \\\\therefore \\\\\tan \alpha=a , \tan \beta = \frac{1}{a}\\\\\tan (\alpha +\beta)= \frac{\tan \alpha+ \tan \beta}{1-\tan \alpha \times \tan\beta}\\\\\text{placing the values we get }\\\\\frac{a+\frac{1}{a}}{1-a\times \frac{1}{a}}\\\\\frac{\frac{a^2+1}{a}}{1-1}$

$frac{\frac{a^2+1}{a}}{1-1}=\infty\\\\\alpha +\beta = \frac{\pi}{2}+k\pi$

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