Question

tan @ + sec @ = cos @ / 1- sin@​

Answer 1

hope it helps you ............

Answer 2

The LHS of the proving statement is given as cosθ/1−sinθ

Multiply and divide by (1+sinθ)

${cosθ(1+sinθ)/(1−sinθ)(1+sinθ)}$

${cosθ+cosθsinθ/1−sin^2θ}$

By the identity, $sin^2θ+cos^2θ=1,$

$=cosθ+cosθsinθ/cos^2θ$

$=cosθ(cosθ)^2+cosθsinθ/(cosθ)^2$

$=1/cosθ+sinθ/cosθ$

$=secθ+tanθ$

Hence proved!

$\huge\mathfrak{Brainliest\: plz}$