Question

Tan ax = cot bx
find the general solution..?..? ​

Answer 1

Answer:

Step-by-step explanation

tanax=cotbx

sinax/cosax = cosbx/sinbx

cosax.cosbx=sinax/sinbx

cosax.cosbx-sinax.sinbx=0

cos(ax+bx)=0

cos(ax+bx)=(2n+1) n.pi/2 [ ←it is the formula of cosx=0]

x(a+b)=(2n+1)n.pi /2

x =(2n+1)n.pi  /2(a+b)

ABHIPSHA....

MARK ME NS BRANILIEST PLZ