Question

tan (C-A/2)=k cot B/2 then k=
a) c-a/c+a b) c+a/c-a
c) c+a/4(c-a) d) c+a/3(c-a) ​

Answer 1

Answer:

The triangle is Right angled triangle

Step-by-step explanation:

cot 2A = ab+c sinA/2cosA/2 = sinAsinBsinC = 2sin 2A .cos 2A 2sin( 2B+C ).cos( 2B−C ) = 2sin 2A .cos 2A 2cos 2A .cos 2B−C sin 2A cos 2A = sin 2A cos 2B−C cos 2A −cos 2B−C =02sin 4B−C+A .sin 4B−C−A =0either,nB−C+A=0 or B−C−A=0∵A+B+C=πSolving the above equationThe triangle is Right angled triangle