Question

(tanθ+cotθ)^2 - (tanθ-cotθ)^2=4

Answer 1

Step-by-step explanation:

What's the question

It's incomplete

Answer 2

Hii !

Solution :-

From LHS

(tan¢ - cot¢ )² - (tan¢ - cot¢)²

break it into , (a+b)²= a²+b²+2ab

and (a-b)² = a²+b²-2ab

since, tan²¢ + cot²¢ +2tan¢*cof¢ - tan²¢ - cot²¢ + 2tan¢ *cot¢

= 4tan¢ *cot¢ =4

°•°tan¢*cot¢ = 1

So proved :-

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