Question

tanα-cotα=2sinα-1/2sinαcosα​

Answer 1

Answer:

$\tan( \alpha ) - \cot( \alpha ) = \frac{2 \sin( \alpha ) - 1 }{2 \sin( \alpha ) \cos( \alpha ) }$

$\tan( \alpha ) - \cot( \alpha ) = \frac{2 \sin( \alpha ) - 1 }{2 \sin( \alpha ) \cos( \alpha ) } \\</p><p></p><p>\frac{ \sin( \alpha ) }{ \cos( \alpha ) } - \frac{ \cos( \alpha ) }{ \sin( \alpha ) } \\ </p><p></p><p>\frac{{\sin}^{2}(\alpha) - { \cos}^{2}(\alpha)} {\sin(\alpha ). \cos( \alpha ) } \\ </p><p> \frac{{\sin}^{2}(\alpha) - {+1} { -\sin}^{2}(\alpha)}{\sin(\alpha ). \cos( \alpha ) } </p><p>$