Question

tan - coto
2 sin²o-
sin cos e
-​

Answer 1

Answer:

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Step-by-step explanation:

LHS=tanθ−cotθ

       =cosθsinθ−sinθcosθ

       =sinθcosθsin2θ−cos2θ

       =sinθcosθsin2θ−(1−sin2θ)

       =sinθcosθ2sin2θ−1

       =RHS

Hence proved