Question

(tan cube theta/ 1+ tan squared theta+ cot cube theta/1+ cot squared theta)= sec theta cosec theta-2 sin theta cos theta
this is my question​

Answer 1

Answer:

(1 – cos2 A) cosec2 A

= (sin2 A) cosec2 A [∵ sin2 A + cos2 A = 1 ⇒1 – sin2 A = cos2 A]

= 12

= 1 = R.H.S

– Hence Proved

2. (1 + cot2 A) sin2 A = 1