Question

(tan e +1/cos e) (tan e - 1/cos e)​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

hey mate there's your answer

=(tan e +1/cose)(tane-1/cose)

=(tane+sece)(tane-sece)

[1/cose =sece]

=(tane+sece)(-1)(sece-tane)

=(-1)(sece+tane)(sece-tane)

=(-1)(sec^2 e -tan^2 e)

[(a+b)(a-b)=(a^2-b^2)]

=(-1)(1)

[sec^2 e -tan^2 e=1]

=-1

hope it helps you......... ...............

thank you!!