Question

Tan inverse 1 + X upon 1 minus x

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Answer:

π/4 + tan^-1 x

Step-by-step explanation:

tan ^-1 ( 1+x / 1-x)

put x = tanA

then

tan ^-1 ( 1+x / 1-x) => tan^-1 (1+ tanA / 1-tanA )

=> tan^-1 [ tan(π/4 + A) ]

tan will be cancelled by its inverse ,then

tan ^-1 ( 1+x / 1-x) => π/4 + A

=> π/4 + tan^-1 x