Question

tan inverse X + 2 cot inverse x

Answer 1

➡HERE IS YOUR ANSWER⬇

${tan}^{ - 1} x + 2 {cot}^{ - 1} x \\ \\ = ( {tan}^{ - 1} x + {cot}^{ - 1} x) + {cot}^{ - 1} x \\ \\ = \frac{\pi}{2} + {cot}^{ - 1} x$

⬆HOPE THIS HELPS YOU⬅