Question

Tan inverse x sin Alpha upon 1 minus x cos aplha

Answer 1

Answer:

here is your answer

Step-by-step explanation:

Given,

tan θ = [(x sin Φ)/(1 – x cos Φ)]

tan θ(1 – x cos Φ) = x sin Φ

tan θ – x tan θ cos Φ = x sin Φ

tan θ = x(tan θ cos Φ + sin Φ)

x = tan θ/(tan θ cos Φ + sin Φ)

Also,

tan Φ = [(y sin θ)/(1 – y cos θ)]

tan Φ(1 – y cos θ) = y sin θ

tan Φ – y tan Φ cos θ = y sin θ

tan Φ = y(tan Φ cos θ + sin θ)

y = tan Φ/(tan Φ cos θ + sin θ)

x/y = [tan θ/(tan θ cos Φ + sin Φ)]/ [tan Φ/(tan Φ cos θ + sin θ)]

= [sin θ/sin(θ + Φ)]/ [sin Φ/sin(Φ + θ)]

= sin θ/sin Φ