tan inverse x+tan inverse2x=phai/2
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Step-by-step explanation:
we first need to know the following relationships between
tan
θ
&
cot
θ
we have:
cot
θ
=
1
tan
θ
also
cot
θ
=
tan
(
π
2
−
θ
)
Explanation:
let
y
=
tan
−
1
x
⇒
x
=
tan
y
x
=
tan
y
⇒
1
x
=
1
tan
y
=
cot
y
1
x
=
cot
y
=
tan
(
π
2
−
y
)
∴
π
2
−
y
=
tan
−
1
(
1
x
)
but
y
=
tan
−
1
x
so
π
2
=
tan
−
1
(
1
x
)
+
tan
−
1
x
as reqd.
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