Question

tan((pi)/(4)+theta)=(1-tan theta)/(1+tan theta)​

Answer 1

Answer:

Step-by-step explanation:I think the sign of the question are messed up... will u check the sign again

Answer 2

Step-by-step explanation:

given

$\tan( \frac{\pi}{4} - \alpha ) = \binom{1 - \tan( \alpha ) }{1 + \tan( \alpha ) } \\ \\ we \: put \: \alpha = \frac{\pi}{4} in \: both \: sides \\ \\ lhs = tan( \frac{\pi}{4} - \alpha ) \\ = \tan( \frac{\pi}{4} - \frac{\pi}{4} ) \\ = \tan(0) \\ = 0 \\ rhs = \tan( \frac{1 - \tan(45) }{1 + \tan(45) } ) \\ = \tan( \frac{1 - 1}{1 + 1} ) \\ = \tan(0) \\ = 0$

LHS = RHS

hence prooved