tan((pi)/(4)+(x)/(2))+tan((pi)/(4)-(x)/(2))=2 sec x Prove it.
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Smple question
we know that tanπ/4 =1
Tan(A+B)={TanA+TanB)/(1-TanATanB)
now using this formula we can write
LHS=(1+Tanx/2)/(1-tanx/2) +(1-tanx/2)/(1+tanx/2)
LHS={(1+tanx/2)^2 +(1-tanx/2)^2}/(1-tan^2x)
LHS=(1+tan^2x/2 +2tanx/2+1+tan^2x/2-2tanx/2)/(sec^2x/2)
LHS=(2+2tan^2x/2)/(sec^2x/2)
LHS=2(1+tan^2x/2)/(sec^2x/2)
=2
LHS=RHS=2
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