Question

[tan( pi-x) tan(1.5pi+x)/cos^2(x-1.5pi)- cos(1.5pi+x)/sin(pi-x)sin^2(2pi-x)=

Answer 1

tan( pi-x) tan(1.5pi+x)/cos^2(x-1.5pi)- cos(1.5pi+x)/sin(pi-x)sin^2(2pi-x)  = 0

Step-by-step explanation:

[tan( pi-x) tan(1.5pi+x)/cos^2(x-1.5pi)- cos(1.5pi+x)/sin(pi-x)sin^2(2pi-x)

tan( pi-x)   = - Tanx

tan(1.5pi+x) = - Cotx

cos^2(x-1.5pi) =  Sin²x

cos(1.5pi+x) = Sinx

sin(pi-x) = Sinx

sin^2(2pi-x) = Sin²x

(-Tan x)(-Cotx) /Sin²x   -  Sinx/SinxSin²x

= (1/Sin²x  -  1/Sin²x)

= 0

tan( pi-x) tan(1.5pi+x)/cos^2(x-1.5pi)- cos(1.5pi+x)/sin(pi-x)sin^2(2pi-x) = 0

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